Aljabar Linear Contoh

$[\begin{array}{c} a & 0 & 0 \\ 0 & b & 0 \\ 0 & 0 & c \end{array}]$

Langkah 1

Find the determinant.

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Langkah 1.1

Choose the row or column with the most $0$ elements. If there are no $0$ elements choose any row or column. Multiply every element in row $1$ by its cofactor and add.

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Langkah 1.1.1

Consider the corresponding sign chart.

$| \begin{array}{c} + & - & + \\ - & + & - \\ + & - & + \end{array} |$

Langkah 1.1.2

The cofactor is the minor with the sign changed if the indices match a $-$ position on the sign chart.

Langkah 1.1.3

The minor for $a_{11}$ is the determinant with row $1$ and column $1$ deleted.

$| \begin{array}{c} b & 0 \\ 0 & c \end{array} |$

Langkah 1.1.4

Multiply element $a_{11}$ by its cofactor.

$a | \begin{array}{c} b & 0 \\ 0 & c \end{array} |$

Langkah 1.1.5

The minor for $a_{12}$ is the determinant with row $1$ and column $2$ deleted.

$| \begin{array}{c} 0 & 0 \\ 0 & c \end{array} |$

Langkah 1.1.6

Multiply element $a_{12}$ by its cofactor.

$0 | \begin{array}{c} 0 & 0 \\ 0 & c \end{array} |$

Langkah 1.1.7

The minor for $a_{13}$ is the determinant with row $1$ and column $3$ deleted.

$| \begin{array}{c} 0 & b \\ 0 & 0 \end{array} |$

Langkah 1.1.8

Multiply element $a_{13}$ by its cofactor.

$0 | \begin{array}{c} 0 & b \\ 0 & 0 \end{array} |$

Langkah 1.1.9

Add the terms together.

$a | \begin{array}{c} b & 0 \\ 0 & c \end{array} | + 0 | \begin{array}{c} 0 & 0 \\ 0 & c \end{array} | + 0 | \begin{array}{c} 0 & b \\ 0 & 0 \end{array} |$

Langkah 1.2

Kalikan $0$ dengan $| \begin{array}{c} 0 & 0 \\ 0 & c \end{array} |$ .

$a | \begin{array}{c} b & 0 \\ 0 & c \end{array} | + 0 + 0 | \begin{array}{c} 0 & b \\ 0 & 0 \end{array} |$

Langkah 1.3

Kalikan $0$ dengan $| \begin{array}{c} 0 & b \\ 0 & 0 \end{array} |$ .

$a | \begin{array}{c} b & 0 \\ 0 & c \end{array} | + 0 + 0$

Langkah 1.4

Evaluasi $| \begin{array}{c} b & 0 \\ 0 & c \end{array} |$ .

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Langkah 1.4.1

Determinan dari matriks $2 \times 2$ dapat dicari menggunakan rumus $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$a (b c + 0 \cdot 0) + 0 + 0$

Langkah 1.4.2

Sederhanakan determinannya.

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Langkah 1.4.2.1

Kalikan $0$ dengan $0$ .

$a (b c + 0) + 0 + 0$

Langkah 1.4.2.2

Tambahkan $b c$ dan $0$ .

$a (b c) + 0 + 0$

Langkah 1.5

Gabungkan suku balikan dalam $a (b c) + 0 + 0$ .

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Langkah 1.5.1

Tambahkan $a (b c)$ dan $0$ .

$a (b c) + 0$

Langkah 1.5.2

Tambahkan $a (b c)$ dan $0$ .

$a (b c)$

$a b c$

Langkah 2

Since the determinant is non-zero, the inverse exists.

Langkah 3

Set up a $3 \times 6$ matrix where the left half is the original matrix and the right half is its identity matrix.

$[\begin{array}{c} a & 0 & 0 & 1 & 0 & 0 \\ 0 & b & 0 & 0 & 1 & 0 \\ 0 & 0 & c & 0 & 0 & 1 \end{array}]$

Langkah 4

Tentukan bentuk eselon baris yang dikurangi.

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Langkah 4.1

Multiply each element of $R_{1}$ by $\frac{1}{a}$ to make the entry at $1, 1$ a $1$ .

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Langkah 4.1.1

Multiply each element of $R_{1}$ by $\frac{1}{a}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} \frac{a}{a} & \frac{0}{a} & \frac{0}{a} & \frac{1}{a} & \frac{0}{a} & \frac{0}{a} \\ 0 & b & 0 & 0 & 1 & 0 \\ 0 & 0 & c & 0 & 0 & 1 \end{array}]$

Langkah 4.1.2

Sederhanakan $R_{1}$ .

$[\begin{array}{c} 1 & 0 & 0 & \frac{1}{a} & 0 & 0 \\ 0 & b & 0 & 0 & 1 & 0 \\ 0 & 0 & c & 0 & 0 & 1 \end{array}]$

Langkah 4.2

Multiply each element of $R_{2}$ by $\frac{1}{b}$ to make the entry at $2, 2$ a $1$ .

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Langkah 4.2.1

Multiply each element of $R_{2}$ by $\frac{1}{b}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 0 & 0 & \frac{1}{a} & 0 & 0 \\ \frac{0}{b} & \frac{b}{b} & \frac{0}{b} & \frac{0}{b} & \frac{1}{b} & \frac{0}{b} \\ 0 & 0 & c & 0 & 0 & 1 \end{array}]$

Langkah 4.2.2

Sederhanakan $R_{2}$ .

$[\begin{array}{c} 1 & 0 & 0 & \frac{1}{a} & 0 & 0 \\ 0 & 1 & 0 & 0 & \frac{1}{b} & 0 \\ 0 & 0 & c & 0 & 0 & 1 \end{array}]$

Langkah 4.3

Multiply each element of $R_{3}$ by $\frac{1}{c}$ to make the entry at $3, 3$ a $1$ .

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Langkah 4.3.1

Multiply each element of $R_{3}$ by $\frac{1}{c}$ to make the entry at $3, 3$ a $1$ .

$[\begin{array}{c} 1 & 0 & 0 & \frac{1}{a} & 0 & 0 \\ 0 & 1 & 0 & 0 & \frac{1}{b} & 0 \\ \frac{0}{c} & \frac{0}{c} & \frac{c}{c} & \frac{0}{c} & \frac{0}{c} & \frac{1}{c} \end{array}]$

Langkah 4.3.2

Sederhanakan $R_{3}$ .

$[\begin{array}{c} 1 & 0 & 0 & \frac{1}{a} & 0 & 0 \\ 0 & 1 & 0 & 0 & \frac{1}{b} & 0 \\ 0 & 0 & 1 & 0 & 0 & \frac{1}{c} \end{array}]$

Langkah 5

The right half of the reduced row echelon form is the inverse.

$[\begin{array}{c} \frac{1}{a} & 0 & 0 \\ 0 & \frac{1}{b} & 0 \\ 0 & 0 & \frac{1}{c} \end{array}]$